load_chembl244_ki#
- skfp.datasets.moleculeace.load_chembl244_ki(data_dir: str | PathLike | None = None, as_frame: bool = False, verbose: bool = False, force_update: bool = False) DataFrame | tuple[list[str], ndarray]#
Load the ChEMBL244 Ki dataset.
The task is to predict the inhibitor constant (Ki) of molecules against the Coagulation factor x target [1] [2].
Tasks
1
Task type
regression
Total samples
3097
Recommended split
activity_cliff
Recommended metric
RMSE
- Parameters:
data_dir ({None, str, path-like}, default=None) – Path to the root data directory. If
None, currently set scikit-learn directory is used, by default $HOME/scikit_learn_data.as_frame (bool, default=False) – If True, returns the raw DataFrame with columns: “SMILES”, “label”. Otherwise, returns SMILES as list of strings, and labels as a NumPy array (1D integer binary vector).
verbose (bool, default=False) – If True, progress bar will be shown for downloading or loading files.
force_update (bool, default=False) – If True, always re-download the dataset from HuggingFace Hub, even if it is already present locally. If False, the dataset is downloaded only if it is not yet available locally.
- Returns:
data – Depending on the
as_frameargument, one of: - Pandas DataFrame with columns: “SMILES”, “label” - tuple of: list of strings (SMILES), NumPy array (labels)- Return type:
pd.DataFrame or tuple(list[str], np.ndarray)
References
Examples
>>> from skfp.datasets.moleculeace import load_chembl244_ki >>> dataset = load_chembl244_ki() >>> dataset (['CC(=N)N1CCC(Oc2ccc3nc(CCC(=O)O)n(Cc4ccc5ccc(C(=N)N)cc5c4)c3c2)CC1, ..., 'CC(=O)N[C@@H](CCC(N)=O)C(=O)N[C@@H](CCCNC(=N)N)C(=O)N[C@@H](CO)C(=O)N[C@H](C=O)CCCNC(=N)N'], \ array([-0.1139, ..., -2.556]))
>>> dataset = load_chembl244_ki(as_frame=True) >>> dataset.head() SMILES Ki 0 CC(=N)N1CCC(Oc2ccc3nc(CCC(=O)O)n(Cc4ccc5ccc(C(... -0.113943 1 CC(=N)N1CCC(Oc2ccc3c(c2)nc(C(C)C)n3Cc2ccc3ccc(... -0.301030 2 CCC(C)c1nc2cc(OC3CCN(C(C)=N)CC3)ccc2n1Cc1ccc2c... -0.518514 3 CC1CCN(C(=O)[C@H](Cc2cccc(C(=N)N)c2)NS(=O)(=O)... -3.301000 4 COC(=O)[C@H]1Cc2ccccc2CN1C(=O)[C@H](Cc1cccc(C(... -4.431000